NoTitleRequired
Junior Member
- Apr 2, 2012
- 184
- 36
I was wondering if anyone has any equations that they use for SEO. Or perhaps just a basic outline of Work + Time + Programs= $$
I'm totally just making this up but how about something like:
T = Time (time in hours working on SEO)
P = Programs/Software (# of programs used)
Pt = Program Time (time in hours program has been running)
Pe = Program Efficiency (the sum of all the programs used in terms of efficiency. a different variable for each program used. 1=lowest, 2=highest)
Kc = Keyword Competition (0=very competitive, 1=no competition)
M = Money ($ x.xx per day)
An example of what the equation might look like:
Kc (T * P ( Pe * Pt )) * 0.002 = M
Here's an example.
T = 30 hours
P = 3 programs
Pt = different for each program
Pe = different for each program
Kc = 0.5
Example of 3 programs used:
Scrapebox => Pe = 1.8 run for 35 hours
BMD => Pe = 1.7 run for 15 hours
AMR => Pe = 1.4 run for 12 hours
SO:
0.5 (30 * 3 ((1.8*35)+(1.7*15)+(1.4*12)) * 0.002 = M
M = $9.50 per day
I think the equation would need to be written by someone with a lot more experience and understanding then me. But i just thought that this would be a cool idea where you could figure out how much work it would take before you even began
I'm totally just making this up but how about something like:
T = Time (time in hours working on SEO)
P = Programs/Software (# of programs used)
Pt = Program Time (time in hours program has been running)
Pe = Program Efficiency (the sum of all the programs used in terms of efficiency. a different variable for each program used. 1=lowest, 2=highest)
Kc = Keyword Competition (0=very competitive, 1=no competition)
M = Money ($ x.xx per day)
An example of what the equation might look like:
Kc (T * P ( Pe * Pt )) * 0.002 = M
Here's an example.
T = 30 hours
P = 3 programs
Pt = different for each program
Pe = different for each program
Kc = 0.5
Example of 3 programs used:
Scrapebox => Pe = 1.8 run for 35 hours
BMD => Pe = 1.7 run for 15 hours
AMR => Pe = 1.4 run for 12 hours
SO:
0.5 (30 * 3 ((1.8*35)+(1.7*15)+(1.4*12)) * 0.002 = M
M = $9.50 per day
I think the equation would need to be written by someone with a lot more experience and understanding then me. But i just thought that this would be a cool idea where you could figure out how much work it would take before you even began