Paying \$50 to whoever can solve this math problem for me

Discussion in 'BlackHat Lounge' started by socialmik, May 25, 2010.

1. socialmikRegular Member

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Hey there, i am willing to paypal anyone \$50 cash if they can solve this simplex problem within the next 2 hours.

Maximize subject to
z= 12x1 + 15x2 + 10x3
2x1 + 2x2 + x3 =< 8
x1 + 4x2 + 3x3 =< 12
x1 >= 0, x2 >= 0, x3 >= 0,

Need it step by step for my teacher as well, easy cash for anyone good in math!

2. BassTrackerBoatsSuper ModeratorStaff MemberModeratorJr. VIP

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It's an Algo, of course it can be gamed.
The answer is potato.

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3. Moto801Senior Member

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There are specific sites out there where you can pay people to do your homework.. not sure if this forum is the right place for it.

Try this site here..

Code:
http://www.assignmentexpert.com/make-my-homework.html

4. srb888Elite Member

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go to a math forum and you'll be able to turn most of them into vegetables ... better them than us.

I only know this:
\$1 +\$2 + \$3 + ... + \$n = lots of dollars for me!

5. kracker2kNewbie

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if x1, x2, x3 and z all = 0 then that solves that problem

6. davanthNewbie

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The answer is finding a divisible sum that can be by 3, and 12 (or less than)

7. cbar126Junior Member

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Use the simplex tableau example here.

personal.maths.surrey.ac.uk/st/D.J.Fisher/MS221/OR-Notes.pdf

8. thedmticBANNEDBANNED

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i think this link will help u :alcoholic

http://www.scribd.com/doc/30673148/Simplex-Method-4th-Semester-Numerical-Programming

9. socialmikRegular Member

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just looked at it, i dont believe x1 and x3 can be negative since the rule is that x1,x2 and x3 are all greater or equal to 0

10. opticbitRegistered Member

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or

check with wolfram alpha.

11. ironlifter76Registered Member

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Maybe I should try math arbitrage...give me the \$50 and I'll go to fiverr where a guy says he'll solve any math problem for you for \$5.

Regards,
ironlifter76:coffee:

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12. fuzonRegistered Member

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Part time explosives expert full time hustler

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13. mjtravis64Newbie

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If we look at 2x1 + 2x2 + x3 =< 8, then we know none of the x's can be greater than 2 if they were all positive. One thing I have found from experience is teachers make mistakes. I found it odd when the variables were qualified in your problem. I still believe my answer is correct.

With that said, I really don't need your money. If you are a student, then you need it for more important things like, beer and getting laid. You are only young once. Live it up.

14. tacopalypseExecutive VIPJr. VIPPremium Member

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z = 60.8
x1 = 2.4
x2 = 0
x3 = 3.2

now send me \$50 and i'll show you how i did it

15. GreyWolfExecutive VIP

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OK, I didn't complete it for you.
I only had a half hour to learn anything about it, but I thought it might still be fun to try it anyway. I could only get halfway through without having a calculator available. But this show the steps toward solving it, you can do the rest to complete it.

I've never even heard of standard maximization problems before and so I didn't have time to learn it enough to solve it completely.

I did the best I could to format a table with characters available. LOL. Since the editor strips out spaces I used dots to space everything out. Just ignore the dots as though they are whitespace.

I know it isn't a complete solution, but maybe it can get you started if you understand it at all. The first steps of solving this up till the point of making the first calculations in the calculator are here:

Maximize: z = 12x1 + 15x2 + 10x3
............. -12x1 - 5x2 -10x3 + z = 0

subject to:
2x1 + 2x2 + x3 s1 ...=< 8 ........\ 2 slack variables
x1 + 4x2 + 3x3 ... s2=< 12 ....../
x1, x2, x3 >= 0 ....................... 3 variables, 3 non basic variables

_...x1...x2...x3...s1...s2...z.|......_
|....2....2....1....1....0....0..|...8..| 8/2=4 smaller non neg entry
|....1....4....3....0....1....0..|.12..| 12/1=12
|--------------------------|----|
|.-12..-5..-10...0....0....1...|..0...|
--.^...............................|.....--
....^most neg indicator
....^pivot on the 2

..1/2 R1 -> R1 ........... *row(1/2,[A],1) -> [A]
.-1 R1 + R2 -> R2 ...... *row(-1,[A],1,2) -> [A]
.12 R1 + R3 -> R3 ...... *row(12,[A],1,3) -> [A]

If I had a calculator or knew how to perform the calculations by hand I could have completed this for you. Just perform the calculations and then you should get the next tableau, and you can continue maximizing till you solve it.

If you can't find the complete solution, hopefully this first half of the problem can get you started so you can complete it yourself.

Good Luck.

16. Nookie MonsterSenior Member

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Try pasting it into a Google search. You'll be surprised at what you find.

17. srb888Elite Member

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Sorry!

18. stevea326Newbie

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That's a simple Linear Programming problem that you can just plug into Excel and get it to maximize for you using the Solver Add-in.

19. UltiGaandNewbie

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i solved it

x2 = 0
x1 = 2.4
x3 = 3.2

max value of z = 60.8

Am too lazy to type full page details here.
In case u need detailed solution PM me.

Last edited: May 26, 2010

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