Some UnAnswerable Questions

rpkrocks

rpkrocks

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Some of you may have heared some "Tricky" questions that do look simple but on the paper are very controversial to answer


Example:

Three Boys Went To The Shop And Purchased Some Items,The overall cost became 20$/Boy.At that instance the shopkeeper was not on the shop,so the cost was decided by the helper.When the shopkeeper came back ,he said to the helper "you overpriced the rate by 5 $,go return the money back ". The Helper was a bit greedy so he kept 2$ in his pocket,and returned 1$ to each of the boys.
​

So After This, Situation Became As Thus:

Charge on Each Boy=19$

Number of Boys =3


i.e,. Total Money On Side of The Three Boys=19X3=57$

Money in Pocket Of Helper=2$

57+2=59 ,So Where Is The One Dollar ?:D


Please Ask Such Question In This Thread ,If You Know Some !:)
 
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I acutally did this as a test with coins, and 1 coin is left on the table. But on paper one dollar is disappearing.
 
The real reason why this doesn't work is because at the end, you aren't supposed to add 57+2=59, as there is no reason to add the 2.

The $2 is already contained within the $57, 55+2=57, so it's 55$ for the item, $2 for the assistant, and $3 refunded.
 
download said:
The real reason why this doesn't work is because at the end, you aren't supposed to add 57+2=59, as there is no reason to add the 2.

The $2 is already contained within the $57, 55+2=57, so it's 55$ for the item, $2 for the assistant, and $3 refunded.
Click to expand...



Nope You Don't Get It:eek:

They Each Bought Items Worth 20$

After 1 $ Is Returned To Each Of Them,Their Cost Price Became 19$ Each i.e,.20-1=19:)
 
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Jeesh... not this again. This is not an unanswerable question but a poorly formulated question. By design it has a mistake in the description so you ASSUME something that is wrong because your TRUST the description.

Charge to each boy was not $19. It was 20-(5/3) = 20-1.66 = $18.34

$18.34*3 = $55

The helper had $2 and each boy got $1 back. So (18.34*3) + (1*3) + 2

That's if you want to calculate it like that though there's no reason for that since the problem was making an incorrect statement from the beginning.
 
rpkrocks said:
Nope You Don't Get It:eek:

They Each Bought Items Worth 20$

After 1 $ Is Returned To Each Of Them,Their Cost Price Became 19$ Each i.e,.20-1=19:)
Click to expand...

He is correct, YOU do not get it.

You have to Ignore $55.00. $55.00 is in the cash register.

So the clerk has $5.00 in his hand and has to make a decision.
He returns $1.00 to each man, and is left with $2.00.
Each man, having spent $19.00, means in total they spent $57.00.
$55.00 in the register and $2.00 in the clerks pocket.


$19 each spent X 3 people = $57
$55 cost of goods + $2 in clerks pocket = $57
$60 originally spent - $3 returned = $57
 
download said:
The real reason why this doesn't work is because at the end, you aren't supposed to add 57+2=59, as there is no reason to add the 2.

The $2 is already contained within the $57, 55+2=57, so it's 55$ for the item, $2 for the assistant, and $3 refunded.
Click to expand...

right, there is no logical reason to add +2 at $57 instead you must subtract 2 from 57 = 55, - the right sum they should pay

another way , they payed 19 x 3 = 57, but they payed 2 more, that 2 should be returned to them as another $3. 60 - 3 - 2 = $55

if the guys would know about the $55 price, they should pay like 18.(3), or $19+$18+$18,etc, but they payed each other $20, so now with this $2 stolen you/we can fuck with others minds, lol.

i knew this trick problem different but the result its the same( 1 missing), so i talked about it before with other people. Some of them didnt understand or didnt wanted - especially the guy who tells it, so i expect u will do the same :D

cheers !
 
madoctopus said:
Jeesh... not this again. This is not an unanswerable question but a poorly formulated question. By design it has a mistake in the description so you ASSUME something that is wrong because your TRUST the description.

Charge to each boy was not $19. It was 20-(5/3) = 20-1.66 = $18.34

$18.34*3 = $55

The helper had $2 and each boy got $1 back. So (18.34*3) + (1*3) + 2

That's if you want to calculate it like that though there's no reason for that since the problem was making an incorrect statement from the beginning.
Click to expand...

This, simple as that.

It's a decimal thing
 
SyZygy said:
This, simple as that.

It's a decimal thing
Click to expand...

I don't know why you guys want to complicate it with Decimals. What the charge was SUPPOSED to be is completely irrelevant to the question. There are no Decimals neccessary in this equation, none exist.

There is $55 in the Register and $2 in the Clerks pocket.
The "charge" is $57.
This is why each man spent $19.00.
 
madoctopus said:
Jeesh... not this again. This is not an unanswerable question but a poorly formulated question. By design it has a mistake in the description so you ASSUME something that is wrong because your TRUST the description.

Charge to each boy was not $19. It was 20-(5/3) = 20-1.66 = $18.34

$18.34*3 = $55

The helper had $2 and each boy got $1 back. So (18.34*3) + (1*3) + 2

That's if you want to calculate it like that though there's no reason for that since the problem was making an incorrect statement from the beginning.
Click to expand...

Some one is really good at math...
 
This one was easy and really old :P

Here is another:
math_conundrum.jpg


Disclaimer: THIS IS NOT TRUE, THERE IS A MISTAKE. Find it, etc. ;p
 
If you reverse the amounts, it adds a dollar.
Someone figure a way to scale this up.;)

Man goes to buy a product for $60.
The store owner then instructs the clerk to refund $5.
The clerk keeps $3 and gives $2 to the man.

Man paid $58
Clerk has $3

Total $61

Rinse and repeat.
 
$20/boy
Total for store = $60

Now teller has to return $5. Total for store = $55 ($60-5)

Teller keeps $2 our of the $5. Returns $1 to each boy (total returned to all boys = $1*3=3).

Total cost of the product for boys = $55 in the store + $2 that was kept by the teller = $57 <- yes, that is the total cost for the boys NOT the total money that changed hands at some point (initial $60 cost for the product).

$57 total cost for boys + $3 that was returned to them = $60 which was original cost
$57 contains the $2 already as somebody here pointed out.

No matter how you spin it, it works. You know why? Because it is f*cking math and math is an exact science. The reason it doesn't add up to you is because you assume something incorrect because it was told to you by the problem. You believed what the description said and you have been deceived.
 
Its for people who haven't heard of BODMAS!!! You need to add first and then subtract!!

2DHades said:
This one was easy and really old :P

Here is another:
math_conundrum.jpg


Disclaimer: THIS IS NOT TRUE, THERE IS A MISTAKE. Find it, etc. ;p
Click to expand...
 
I believe I know the answer to this question:

noOrH
 
Last edited:
Here's another tricky question:

A ball falls from a cliff of height 491.5m in 10 seconds. What is the color of the bear of that region?

The difference between this question and the OP's question is that this question isn't flawed.
 
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ok...........ok Guys .....That Was a Stupid Question ,it was just For EXAMPLE


But I Asked You Guys To Add More "difficult" Kinda Queries :D

Except MR.Paincake and 2dhades No One Seems To Add in The List :(
 
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