scripting ig follow/unfollow on one account

J

JBrewster

Junior Member

Apr 24, 2020

188

19

• Jun 13, 2020

• #1

Hi members

I use iMacros for several scripts on ig including mass canceling pending requests. I however have not found a script that can do a F/U on one singl account

For example:

I go on X Account I follow it then unfollow it with maybe 0 seconds in between, I want to keep doing this repeatedly many times.

Thanks for all inputs

 

HustleTong

Elite Member

May 30, 2019

13,466

10,660

• Jun 13, 2020

• #2

You need wait 8-12 hours to let someone follow you back.

 

J

JBrewster

Junior Member

Apr 24, 2020

188

19

• Jun 13, 2020
• Thread Starter Thread Starter

• #3

HustleTong said:

You need wait 8-12 hours to let someone follow you back.

Click to expand...

If you are saying this in regards to IG algorithims, Im not concerned about it right now. The reason why I am asking for this script is to test something out.

 

mnunes532

Elite Member

Jan 21, 2014

2,131

826

• Jun 13, 2020

• #4

So, you want a javascript script to simply follow/unfollow the same user within x seconds?

 

J

JBrewster

Junior Member

Apr 24, 2020

188

19

• Jun 13, 2020
• Thread Starter Thread Starter

• #5

mnunes532 said:

So, you want a javascript script to simply follow/unfollow the same user within x seconds?

Click to expand...

Exactly
Im hoping I can get a script for iMacros specifically but not possible then thats fine to

 

mnunes532

Elite Member

Jan 21, 2014

2,131

826

• Jun 13, 2020

• #6

Try this piece of code

setInterval(function(){
document.getElementsByClassName("vBF20 _1OSdk")[0].click();
}, 3000);

 

J

JBrewster

Junior Member

Apr 24, 2020

188

19

• Jun 16, 2020
• Thread Starter Thread Starter

• #7

mnunes532 said:

Try this piece of code

setInterval(function(){
document.getElementsByClassName("vBF20 _1OSdk")[0].click();
}, 3000);

Click to expand...

This is the message I got:
SyntaxError: can not parse macro line 1: setInterval(function){

 

mnunes532

Elite Member

Jan 21, 2014

2,131

826

• Jun 16, 2020

• #8

Because that is javascript code. Open console of browser, paste that code and check if it works.

 

J

JBrewster

Junior Member

Apr 24, 2020

188

19

• Jun 17, 2020
• Thread Starter Thread Starter

• #9

mnunes532 said:

Because that is javascript code. Open console of browser, paste that code and check if it works.

Click to expand...

I pasted it into console and clicked enter
still nothing