Output for below code

reddensoft · Nov 8, 2022

What is the output of the below code?

#include <stdio.h>

int main()

{

int arr[5]={10,20,30,40,50,21};

printf("%d", arr[6]);

return 0;

}

r4y · Nov 8, 2022

just run it?

Zooker · Nov 11, 2022

There are many compilers where you can test code right in the browser.

However, that code won't compile. The variable is declared to be of size 5 but it has 6 items. Fixing that, arrays are 0-based in C/C++ so the arr[6] references uninitialized memory. So you'll either get a random value or it'll just crash.

If you're working on code, the online compilers are great and you can work on code and run it right in the browser.

IonicStudio · Dec 2, 2022

Hi sir, this will cause the index to be out of bounds

PasserbyA · Dec 25, 2023

Zooker said:
There are many compilers where you can test code right in the browser.

However, that code won't compile. The variable is declared to be of size 5 but it has 6 items. Fixing that, arrays are 0-based in C/C++ so the arr[6] references uninitialized memory. So you'll either get a random value or it'll just crash.

If you're working on code, the online compilers are great and you can work on code and run it right in the browser.

Even though its array has only 5 elements, it outputs the value of the 6th element by pointer shifting.
Given the simplicity of the program, it won't crash. Therefore, the output should be the first four bytes of the main function's return address.

Output for below code

reddensoft

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r4y

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PasserbyA

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