Need PHP help

DaBomb · Jul 28, 2009

having a difficult time with this.. wondering if anyone here can help.

Let's say I have the following URL string:

Code:

http://www.google.com/search?hl=en&blah=0123456789&safe=off&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&hs=cf

I need to replace the value of blah, blah is always 10 characters. the position of blah can change within the URL string.

Thanks in advance!

geezer101 · Jul 28, 2009

I'm sure you can find what you need here http://www.w3schools.com/PHP/php_ref_string.asp If the string always contains blah= then it shouldn't be too tricky. If not you might have to use regular expressions.... Google php regex

DaBomb · Jul 28, 2009

I'm familiar with that page and php string concepts.. just having a difficult time with this

justin · Jul 28, 2009

Code:

<?php
echo str_replace("blah=","replacedvalue","yourURL");
?>

try this?

DaBomb · Jul 28, 2009

justin said:
Code:

<?php echo str_replace("blah=","replacedvalue","yourURL"); ?>

try this?

That won't work... it would only replace blah=, and the not the value of it.

this worked:

Code:

                    $text = "http://www.google.com/search?hl=en&blah=0123456789&safe=off&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&hs=cf";
                    $InjectedValue = "999999999";
                    
                    $StartPos = strripos($text,"blah="); 
                    $textFront = substr($text, 0, $StartPos+5);
                    $textEnd = substr($text, $StartPos+15);
                    $text = $textFront . $InjectedValue . $textEnd;

cyklotrial · Jul 28, 2009

simple regex

PHP:

<?php
$string = 'http://www.google.com/search?hl=en&blah=0123456789&safe=off&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&hs=cf';
$pattern = '/blah=........../i';
$replacement = 'blah=I_LOVE_BHW';
echo preg_replace($pattern, $replacement, $string);
?>

regards
Lukas

DaBomb · Jul 28, 2009

cyklotrial said:

simple regex

PHP:

<?php
$string = 'http://www.google.com/search?hl=en&blah=0123456789&safe=off&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&hs=cf';
$pattern = '/blah=........../i';
$replacement = 'blah=I_LOVE_BHW';
echo preg_replace($pattern, $replacement, $string);
?>

regards
Lukas

that's exactly what I was looking for, but my regex sucks, so I took the easy way out.

what regex can I use that will match blah=9999999999 (i.e. blah= followed by 10 integers)

GridPanel · Jul 29, 2009

You can use this if you want to go the regex way:

PHP:

<?php
$url = 'http://www.google.com/search?hl=en&blah=0123456789&safe=off&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&hs=cf';
$key = 'blah';
$replace = 'HelloWorld';
echo preg_replace("#{$key}=[^&]+&#", "{$key}={$replace}&", $url);
?>

That will replace everything from the = right up to the &.

fukinlee · Aug 13, 2009

Simple:

Code:

$replacement_value = 'ILikeBoobs';
$query = 'http://www.google.com/search?hl=en&blah=0123456789&safe=off&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&hs=cf';
$new_query = preg_replace('/blah=.+&/', 'blah='.$replacement_value.'&', $query);
//$new_query will be http://www.google.com/search?hl=en&blah=ILikeBoobs&safe=off&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&hs=cf

00CivicEX · Aug 14, 2009

i think your pregreplace needs to be

PHP:

/blah=.+[0-9]

Cause your's will match everything from the .+ The one I posted will only grab the numbers

Need PHP help

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