you said that "bet $5 on the red
(if black wins..) double it ($10) and bet on the black and keep doing it till you win" and then you said "is not betting on the same color over and over again"
so it's still betting on same color ?![]()
bet $5 on the red
(if black wins..) double it ($10) and bet on the black and keep doing it till you win..
if you can read, you bet on the red first, if the black wins (means you lost that red bet) you bet on the black.. how come that is betting on the same color lol
It does not work for the simple reason you cant double up enough times to get your money back if you go on a losing streak.
eg.$5 and lose then you bet $10 and lose next its $20, $40, $80 , $160 then $320 which you cant bet because the maximum bet limit is $300..so its bs
bet limit is 320? well i never got to that point i had to bet over $18 to get my money back.. but the $5 was just an example i myself started with $0,50 and $1 only.. and i limtied myself to $20-$30 per day and max of $120 per week on the same betting house. and i do it online noton a real casino.
It does not work regardless of what colour you bet on as that doesn't change the odds of the bet.
Law of large numbers says that everything always arrives at its expected value and you have a -EV on every single roulette bet no matter what. There is no way to win at roulette over a large sample.
Martingale system (outlined by OP) only works in a scenario in which table limits are non existant and bankroll is infinite.
Sure, losing a 50/50 bet (though sleightly less than 50/50 due to 0 and 00 in roulette) eight times in a row only happens once in 256, when this occurs (CERTAIN to happen eventually), you will lose $1270, and most likely all the profit you have made.
with the profit i already have, if i lose lets say 7 or 8 in a row i will just stop for the day and move to another betting house.. and since i start the bet with only $1 if i lose, i only lose about $150
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