Hi i have a question its fairly simple but i just cant get my head round it. I need to multiply out and than simplify the following equation. a(b-c) +b (c-a) I have the answer but i need to know how to get to the answer , The answer is = c(b-a) if any help on how you get that answer will be of great help.

a(b-c) +b(c-a) = ab -ac +bc -ba = ab -ba -ac +bc = -ac + bc = c (b-a) [Answer] I think that's the true answer.

thanks for the reply can you tell me how you got from =ab-ac+bc-ba to = ab-ba-ac+bc to = -ac+bc = c=(b-a) If you are busy please do not reply i do not want to waste peoples time sir

=ab -ac +bc -ba // rearranging = ab - ba -ac + bc // ab and ba are equal to each other ab=ba // so ab - ba =0 = -ac + bc //taking c as common = c(-a + b) //rearranging = c(b - a) [ANswer]

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