Can you find the output of this coding?

seoways said:

Code:

int i=5;
int j=i+++++i;

Click to expand...

Invalid syntax...

You may either do i++ or ++i, i've provided a sample for you to give you an idea of what the difference is.

Code:

int firstNumber = 5;
int secondNumber = 0;

Console.WriteLine("Initial values");
Console.WriteLine(">>> First number: {0}", firstNumber);
Console.WriteLine(">>> Second number: {0}", secondNumber);

secondNumber = firstNumber++;

Console.WriteLine("\nA reference of the first numbers value is passed to the second number before first number is incremented");
Console.WriteLine(">>> Compute: secondNumber = firstNumber++;");
Console.WriteLine(">>> First number: {0}", firstNumber);
Console.WriteLine(">>> Second number: {0}", secondNumber);

Console.WriteLine("\n##########\nReset values\n##########\n");

firstNumber = 5;
secondNumber = 0;
Console.WriteLine("Initial values");
Console.WriteLine(">>> First number: {0}", firstNumber);
Console.WriteLine(">>> Second number: {0}", secondNumber);

secondNumber=++firstNumber;
Console.WriteLine("\nFirst number is incremented, and then a reference of the first number is assigned to the second number");
Console.WriteLine(">>> Compute: secondNumber = ++firstNumber;");
Console.WriteLine(">>> First number: {0}", firstNumber);
Console.WriteLine(">>> Referenced number: {0}", secondNumber);

Click to expand...

divok said:

90% sure it would be a error in c .
because a variable(i) is being accessed more than once in a single assignment operation

Click to expand...

seoways said:

It is definitely not an error code....
We can access the value of a variable(i) at any number of time in a single line of coding.
Don't you know this simple basics!!!:thumpdown

Click to expand...

botrockets said:

j = 12 is the answer as said by sOap

Click to expand...