I have a quiz tomorrow and I'm pretty much able to solve everything in this chapter. But there is this one question that i'm don't even know how to start and it's probably going to appear on the quiz tomorrow. Any help ? http://i47.tinypic.com/25ouuzp.png PLZ explain how you got the answer.

Did you attempt the question? It's pretty easy. Simplify the first expression of the function, plug f(x) into the second equation when x = 2 ... do the same for x = 3 (essentially). I'm too lazy to write this out, so I must say if you just searched this on Google, you would have found the answer http://answers.yahoo.com/question/index?qid=20100927182406AAqOnL6

funny how somebody asked almost the exact same question 2 years ago on yahoo answers lol. you've got a function that's split up into 3 parts. each part is defined by one of the equations. the parts are joined together at locations x=2 and x=3. in order to make the whole function continuous, you need to determine values for a and b such that at the locations x=2 and x=3, the 2 adjoining functions there have the same y-values. so you plug in x=2 for the left and middle functions and set them equal to each other, and you'll have an equation in terms of just a and b. then you plug in x=3 for the middle and right functions, set then equal to each other, and you have another equation in terms of a and b. then just use plain algebra to solve the system of 2 equations with 2 unknowns and you have your answer.