Help with PHP, $_GET variable

[sonic1234]

Hello,

I need a little help with this function.

Suppose my url is: http://testurl.com/index.php?value=3
and i write: $result = $_GET['value'];
I will get answer as $result = 3

But if my url is: http://testurl.com/index.php
I get an error because $_GET['value'] has no value, how to rectify this error?

 

[Porthos]

Use a condition to only establish the $result variable if the $_GET['value'] variable exists.

if($_GET['value']){$result=$_GET['value'];}

 

[sonic1234]

With this i get this error: Undefined variable: _Get

 

[Porthos]

Try this:
if(isset($_GET['value'])){$result=$_GET['value'];}

Mind if I ask what version of PHP you're using?

 

[hameem]

With this i get this error: Undefined variable: _Get

Check your syntax. Check everything is there like this "$_GET['value']" without the double quotes of course. If that doesn't help, paste that part of the code here.

 

[Stalli0n]

you can check with isset if a variable is set

So in your example:

if (isset($_GET['value']))
{
    $result = $_GET['value'];
}

 

[sonic1234]

The part of code is

if (isset($_Get['page']))
$page = $_GET['page'];
else
$page = 1;

With issest whatever the condition is, the script always executes with else. Even if index.php?page=5 the script will go in else. $page is always 1, with isset.

 

[sonic1234]

I am using:
Apache Version :2.2.21 PHP Version :5.3.10

 

[MickMcG]

u can use an alternative to above which will also set a default value (if u havent already previously in ur code):

$result = ( isset( $_GET['value'] ) ) ? $_GET['value'] : "";

the error u got "Undefined variable: _Get" is cos u forgot the $ sign in the $_GET part

 

[plumbum416]

With issest whatever the condition is, the script always executes with else. Even if index.php?page=5 the script will go in else.

Thats because $_GET is case sensitive and you wrote

isset($_Get['page'])

instead of

isset($_GET['page'])

 

[MickMcG]

edit: answered above

 

[sonic1234]

Thanks a lot Mick, this code worked

$result = ( isset( $_GET['value'] ) ) ? $_GET['value'] : "";

But can somebody tell me why, if else dint work it was same as the above code:

if (isset($_Get['value']))
$result = $_GET['value'];
else
$result = 1;

 

[BleuMunkiGraphics]

Thats because $_GET is case sensitive and you wrote

isset($_Get['page'])

instead of

isset($_GET['page'])

true. php is fussy. Remember your Case

 

[sonic1234]

Oh ok, i get it now, thanks a lot guys for your help and time