# Need some help with math homework (college algebra) -Free Jr. VIP Upgrade!

Discussion in 'BlackHat Lounge' started by Essential Clix, May 4, 2009.

1. ### Essential ClixExecutive VIPPremium Member

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My girlfriend is overloaded with assignments for college right now and is really stressing out because the deadline is this Wednesday. I absolutely suck at math, so if any of you have any spare time, please help her (us) out with the math problems below. Judging by the look of this stuff, it has to do with graphing, intercepts, and slopes (from what I can remember).

There's a Jr. VIP upgrade in it for the first person who can provide both the answers AND the steps/methods to solve the problems. If you're already a Jr. VIP, then you'll get another year's worth of Jr. VIP status on me.

A. Graph the following equations:

1. 3x-y=9
2. y=-2/5x+1 (that's negative two-fifths x)
3. y=x2-x-1 (that's x to the 2nd power)
B. Determine the slope of the described lines:

1. Passing through (-2,1) and (4,6)
2. Parallel to y=-4x+5
C. Write the equations of the described lines:

1. Slope is 2/3, passing through (0,4)
2. Passing through (2,-1) and (4,6)
3. Passing through (3,-5) and perpendicular to y=-4x+5
4. Passing through (-2,1) and parallel to 2x-y=7
5. Slope is -2/3 and passing through (5,4)
Good luck and thanks!

2. ### berrycorpGuest

these questions are real easy...!

m in 3rd year mech engg.... so it seems kiddish...! really!

A) in each just put one 0 each... ie... once take x=0 , once y=0 u get 2 points... join then... thats ur ans

the 3rd part is a curve... when u square root u get 2 points... one + and one -ve... so thats a curve.. i think u can plot that!

b) in this u use the formulae... theta= tan-1 (p/b)... where p=perpendicular and b=base

c) in this u need to use the formula for line formation... if u dont know what it is... its

Y=mx+c

i'll kill u if u ask what the equation means! i already think i have helped a lot!

and this really is very very very easy stuff!

and i am not posting coz of jr VIP thing... i became a jr vip before the new rules came in place... i dont even need to donate as i will be a jr vip without it too....!

i just posted coz i think this is super easy!

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3. ### blackmagiquellcBANNEDBANNED

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I will do these for you

I am a math major and I love to help out BHW members.

PM me the questions please (copy paste)

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4. ### crappypasteJunior Member

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This is my answer for letter A (I'm a n00b )

I hope that's enough for 1/3 of the prize, haha lol

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Last edited: May 4, 2009

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2.Passing through (2,-1) and (4,6)
-Use rise over run formula to find slope.
(6 - (-1)) / (4 - 2) = 7/2 (3.5)
-Plug in values (2,-1) to find b.
-1=(3.5)2+b
-1=7+b
-7
-8=b
3. Passing through (3,-5) and perpendicular to y=-4x+5
-To find the equation perpedicular to y=-4x+5 we switch x and y and solve for y
y=-4x+5 becomes x=-4y+5
x=-4y+5
-5
x-5=-4y
/(-4)
(x-5)/4=y --> y=.25x-(5/4)
-Now we now the slope of our perpedicular line is .25, now we use the point (3, -5) to find b
-5=.25(3)+b
-5=.75+b
-.75
-5.75=b
4. Passing through (-2,1) and parallel to 2x-y=7
-Solve 2x-y=7 into graphing form.
2x-y=7
-2x
-y=-2x+7
*(-1)
y=2x-7
-Now we now the slope is 2. Solve for b by plugging in (-2, 1)
1=2(-2)+b
1=-4+b
+4
5=b
5.Slope is -2/3 and passing through (5,4)
-Plug in (5,4) to find b
4=(-2/3)5+b
4=(-10/3)+b
+(10/3)
7.333=b

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Sorry didnt get all of it the first time....

A. Graph the following equations:

1. 3x-y=9
2. y=-2/5x+1 (that's negative two-fifths x)
3. y=x2-x-1 (that's x to the 2nd power)

B. Determine the slope of the described lines:

1. Passing through (-2,1) and (4,6)
2. Parallel to y=-4x+5

C. Write the equations of the described lines:

1. Slope is 2/3, passing through (0,4)
2. Passing through (2,-1) and (4,6)
3. Passing through (3,-5) and perpendicular to y=-4x+5
4. Passing through (-2,1) and parallel to 2x-y=7
5. Slope is -2/3 and passing through (5,4)

Good luck and thanks!
A. Graph the following equations:
1. 3x-y=9
- Solve into graphing form
3x-y=9
-3x
-y=-3x+9
* -1
y=3x-9
-Graph
2. y=-2/5x+1
-Graph
3. y=x2-x-1
- Graph
B. Determine the slope of the described lines:
1. Passing through (-2,1) and (4,6)
-Slope is found by finding "rise over run" (y2 - y1) / (x2 - x1)
(6 - 1) / (4 - (-2)) = 5/6 (5 sixths)
2. Parallel to y=-4x+5
-Any line Parallel to a linear equation will have the same slope as that equation.
C. Write the equations of the described lines:
1.Slope is 2/3, passing through (0,4)
-Standard linear equation line is y=mx+b (we must solve for b, we already have m)
-Plug in 0 for X and 4 for y
4=(2/3)0+b
4=b
2.Passing through (2,-1) and (4,6)
-Use rise over run formula to find slope.
(6 - (-1)) / (4 - 2) = 7/2 (3.5)
-Plug in values (2,-1) to find b.
-1=(3.5)2+b
-1=7+b
-7
-8=b
3. Passing through (3,-5) and perpendicular to y=-4x+5
-To find the equation perpedicular to y=-4x+5 we switch x and y and solve for y
y=-4x+5 becomes x=-4y+5
x=-4y+5
-5
x-5=-4y
/(-4)
(x-5)/4=y --> y=.25x-(5/4)
-Now we now the slope of our perpedicular line is .25, now we use the point (3, -5) to find b
-5=.25(3)+b
-5=.75+b
-.75
-5.75=b
4. Passing through (-2,1) and parallel to 2x-y=7
-Solve 2x-y=7 into graphing form.
2x-y=7
-2x
-y=-2x+7
*(-1)
y=2x-7
-Now we now the slope is 2. Solve for b by plugging in (-2, 1)
1=2(-2)+b
1=-4+b
+4
5=b
5.Slope is -2/3 and passing through (5,4)
-Plug in (5,4) to find b
4=(-2/3)5+b
4=(-10/3)+b
+(10/3)
7.333=b

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If i am given the jr. vip status I will also make graphs to go along with section A

8. ### lolcongratsJunior Member

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ill do it, pming

EDIT: Fuck too late...

9. ### stealthisblogRegular Member

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im doin them all with all the steps and instructions, should be done soon

INCLUDING GRAPHS

10. ### crashedSenior Member

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Wow, essential clix you have caused a math storm, so many experts here to count their bank! Just wish I could hire someone to sit my finals for me...

11. ### stealthisblogRegular Member

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ok, im done. i just wanna know, will i get jr vip if i upload everything (graphs, steps, etc)? I dont wanna waste time scanning if i wont

12. ### abhi1Power Member

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I'll go to college on behalf of ur gal make me a Jr. VIP...

(yea, am kidding...)

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Ok just to be safe

nvida.com/pics/graph1.JPG
nvida.com/pics/graph2.JPG
nvida.com/pics/graph3.JPG

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roflshome copied answers straight out of my post btw

15. ### BHFr3shYJunior Member

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Last edited: May 4, 2009
16. ### billu512Power Member

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If U Have Any Other Problems Let Me Know lol I Will Ask My Teacher To Solve Them Free Of Cost

P.S. People Are Too Fast

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I don't think that pastbin'ing my post character for character was very smart

18. ### shylessonPower Member

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If her college teacher is anything like the teachers I had in college, they'll want every freakin step including the adding and subtracting so I outlined it out for ya:

19. ### Hoops4meJunior Member

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I have to correct the newbs answer to part B

The slope of a line is determined as Y= mx + b

where m is the slope and b is the y intercept.

The questions states a line parallel to Y = -4x + 5

the slope of the line is negative 4 since parallel lines have the same slope.

For part 1 of B.

I would graph it out on paper.

Locate the 2 points (-2,1) (x,y) and (4,6) in this case and draw a line between them.

Determine the rise/run of the line

In this case rise is found from line going from -2 to 4 = 6

run is 1 to 6 = 5

Therefore the slope is 6/5.

Make sure to check if the slope is positive or negative.

A positive slope is a rising line and a negative slope is a declining line.

I hope I explained the theories behind Part B. I think it is important to understand the process of how to do a problem, not just memorize a particular problem.

PM me if you need some help. I have a MS in Engineering. Out of work due to health issues.

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