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How do i achieve this?

Discussion in 'Black Hat SEO' started by frazgta, Aug 18, 2012.

  1. frazgta

    frazgta Power Member

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    Lets say i have 5 keywords that i want to use as anchor texts:
    A
    B
    C
    D
    E

    Now i want to the keyword A to appear 25% and the rest (B,C,D,E) to each have a 18.75% chance of appearing. In simple words:

    {A|B|C|D|E}

    In the above i want A to come up 1 out of 4 times and the rest to come up randomly.

    Is that possible?

    How do i achieve this in SENukeX?
     
  2. frazgta

    frazgta Power Member

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    Come on guys 324 views and no reply lol :)
     
  3. lancis

    lancis Elite Member

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    Depends on the precision you want you'll have to create a longer list:

    {A|A|A|B|B|C|C|D|D|E|E}

    Now A has a 27.27% chance to appear, and B has 18.18% chance to appear.
     
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  4. Glenn BH

    Glenn BH Regular Member

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    Lancis is right. With {A|A|A|A|B|B|B|C|C|C|D|D|D|E|E|E} you can achieve the numbers in your first post (25% - 18.75%) but if it doesn't need to be that precise lancis' list works great.
     
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  5. frazgta

    frazgta Power Member

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    Thanks for the help.
    This is all theoretical and dependedent on probability still i will post the results.
    lets see :)
     
  6. Junkfood00

    Junkfood00 Elite Member

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    I'm not sure, but I think this works: {A|{B|C|D|E}|{B|C|D|E}|{B|C|D|E}}

    I think it gives exactly 25% probability for A and 18.75% for the rest. I might be wrong though.
     
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  7. frazgta

    frazgta Power Member

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    Genius mate. Genius!
     
  8. frazgta

    frazgta Power Member

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    Interesting results:

    For
    {A|{B|C|D|E}|{B|C|D|E}|{B|C|D|E}}

    A came out 1 out of 4 times a total of 8 times before not appearing. Then appeared again a lot of times. So test was conclusive.
    {A|{B|C|D|E}|{B|C|D|E}|{B|C|D|E}} gives A an exact 25% chance of appearing.
     
  9. soma56

    soma56 Regular Member

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    Talk about mindfuc@#ing. I swear people can spend four years in university getting a bachelors degree in search engine optimization.
     
  10. Junkfood00

    Junkfood00 Elite Member

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    Yeah, the probability for A is obvious, but what about B C D E?

    I'm actually pretty good at maths but this probability stuff is not my thing, it twists my head really hard.
     
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  11. dubious

    dubious Regular Member

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    If you want to get creative with your spintax, you can implement some methods like traditional huffman encoding to ensure that you have the desired frequency distribution of your anchors. (Think of each | as a 0 and a 1 and then it gets interesting with nested spintax.).
     
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  12. frazgta

    frazgta Power Member

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    A has 25% probability (1 out of 4)
    {B,C,D,E} have 75% (3 out of 4)
    out of that 75% I THINK B,C,D,E, them 4 have 75/4=18.75% chance of occurring each

    So
    A=25%
    B=18.75%
    C=18.75%
    D=18.75%
    E=18.75%

    Total=100%
     
  13. frazgta

    frazgta Power Member

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    I have NO idea what your talking about lol
    Some examples would explain it better.